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IBM C9050-041 Exam Syllabus Topics:
| Section | Objectives |
|---|---|
| Topic 1: File and I/O Handling | - Input/Output statements and file access |
| Topic 2: Advanced PL/I Topics | - Pointers, bit manipulation and system constructs |
| Topic 3: Control Structures | - Conditional and iterative constructs |
| Topic 4: PL/I Fundamentals | - Basic PL/I syntax and structure - Data types and declarations |
| Topic 5: Procedures and Functions | - Procedure declaration and invocation |
IBM Programming with IBM Enterprise PL/I Sample Questions:
CORRECT TEXT
Given the following code, which value is output on the last line?
DCL N FIXED BIN (31);
DCL X FIXED BIN (31) INIT (0);
DON = 1 TO 7, 11 TO 15 WHILE (X< 20);
X = N*N;
PUT SKIP LIST (X);
END;
- A. 49
- B. 25
- C. 121
- D. 16
Correct Answer: A 🗳️
CORRECT TEXT
When the following program is executed, the compiler will produce this warning message: "FIXED
DEC(7,2) operand will be converted to FIXED OIN(25,7).
Significant digits may be lost."
The best way to fix this problem and have the output value be 29.20 is to change the last
assignment statement to which of the following?
TEST: PROC;
DCL
1 REC_OUT,
03 AVAIL FIXED BIN(31),
03 TOTAL_SPARE FIXED DECIMAL(7,2),
03 WORK_TOTAL FIXED DECIMAL(7,2);
AVAIL= 17;
WORK_TOTAL = 12.2;
TOTAL_SPARE = AVAIL + WORK_TOTAL
PUT SKIP LIST( TOTAL_SPARE); END;
- A. TOTAL_SPARE = BIN( AVAIL + WORK_TOTAL);
- B. TOTAL_SPARE = AVAIL + BIN( WORK_TOTAL);
- C. TOTAL_SPARE = DEC(AVAIL) + WORK_TOTAL;
- D. TOTAL_SPARE = DEC( AV AIL + WORK_TOTAL);
Correct Answer: C 🗳️
CORRECT TEXT
What is the result, if any, or executing the following code?
DCL A BIT(1) INIT('0'B);
DCLB BIT(1) INIT('0'B);
DCLC BIT(1) INIT('1'B);
A = ^B & C;
- A. The value of A is 'OS.
- B. There is no result because the syntax is wrong.
- C. The value of A is'1'S.
- D. The value of A is unpredictable.
Correct Answer: C 🗳️
CORRECT TEXT
Given the following piece of code, what will happen when the code is executed if STRINGSIZE is not enabled?
DCL X CHAR (5) INIT ('ABCDE');
DCL Y CHAR (3) INIT (");
Y = X;
- A. Y receives the value 'ABC' and the next two bytes following Y's storage are overridden by 'DE'.
- B. The assignment is not executed and program execution continues after the assignment.
- C. Y receives the value 'ABC' and 'DE' is not assigned to any storage area.
- D. The assignment is not executed and program execution abends.
Correct Answer: C 🗳️
CORRECT TEXT
What happens, if anything, after end of rile has been reached in the following code?
DCL INF FILE RECORD INPUT;
DCL INFIELD CHAR(100) BASED(P);
DCL P PTR;
DCL EOF BIT(1) INIT('0'B);
ON ENDFILE(INF) BEGIN;
EOF = '16;
ALLOC INFIELD;
INFIELD = 'EOF REACHED';
END;
OPEN FILE(INF);
READ FILE(INF) SET(P);
DO WHILE(^EOF);
READ FILE(INF) SET(P);
END;
- A. Nothing because end of file will never be reached.
- B. INFIELD will have a value 'EOF REACHED' and the program ends.
- C. Runtime error because there
SE statement. - D. There will be an infinite
loop.
Correct Answer: B 🗳️
